214 lines
7.6 KiB
Java
214 lines
7.6 KiB
Java
// Copyright (c) 2013-2014 Sandstorm Development Group, Inc. and contributors
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// Licensed under the MIT License:
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//
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// Permission is hereby granted, free of charge, to any person obtaining a copy
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// of this software and associated documentation files (the "Software"), to deal
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// in the Software without restriction, including without limitation the rights
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// to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
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// copies of the Software, and to permit persons to whom the Software is
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// furnished to do so, subject to the following conditions:
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//
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// The above copyright notice and this permission notice shall be included in
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// all copies or substantial portions of the Software.
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//
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// THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
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// IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
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// FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
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// AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
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// LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
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// OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
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// THE SOFTWARE.
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package org.capnproto;
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import java.io.IOException;
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import java.nio.channels.WritableByteChannel;
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import java.nio.ByteBuffer;
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public final class PackedOutputStream implements WritableByteChannel {
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final BufferedOutputStream inner;
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public PackedOutputStream(BufferedOutputStream output) {
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this.inner = output;
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}
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public int write(ByteBuffer inBuf) throws IOException {
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int length = inBuf.remaining();
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ByteBuffer out = this.inner.getWriteBuffer();
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ByteBuffer slowBuffer = ByteBuffer.allocate(20);
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int inPtr = inBuf.position();
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int inEnd = inPtr + length;
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while (inPtr < inEnd) {
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if (out.remaining() < 10) {
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//# Oops, we're out of space. We need at least 10
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//# bytes for the fast path, since we don't
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//# bounds-check on every byte.
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if (out == slowBuffer) {
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int oldLimit = out.limit();
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out.limit(out.position());
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out.rewind();
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this.inner.write(out);
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out.limit(oldLimit);
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}
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out = slowBuffer;
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out.rewind();
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}
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int tagPos = out.position();
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out.position(tagPos + 1);
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byte curByte;
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curByte = inBuf.get(inPtr);
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byte bit0 = (curByte != 0) ? (byte)1 : (byte)0;
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out.put(curByte);
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out.position(out.position() + bit0 - 1);
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inPtr += 1;
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curByte = inBuf.get(inPtr);
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byte bit1 = (curByte != 0) ? (byte)1 : (byte)0;
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out.put(curByte);
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out.position(out.position() + bit1 - 1);
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inPtr += 1;
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curByte = inBuf.get(inPtr);
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byte bit2 = (curByte != 0) ? (byte)1 : (byte)0;
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out.put(curByte);
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out.position(out.position() + bit2 - 1);
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inPtr += 1;
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curByte = inBuf.get(inPtr);
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byte bit3 = (curByte != 0) ? (byte)1 : (byte)0;
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out.put(curByte);
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out.position(out.position() + bit3 - 1);
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inPtr += 1;
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curByte = inBuf.get(inPtr);
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byte bit4 = (curByte != 0) ? (byte)1 : (byte)0;
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out.put(curByte);
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out.position(out.position() + bit4 - 1);
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inPtr += 1;
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curByte = inBuf.get(inPtr);
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byte bit5 = (curByte != 0) ? (byte)1 : (byte)0;
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out.put(curByte);
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out.position(out.position() + bit5 - 1);
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inPtr += 1;
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curByte = inBuf.get(inPtr);
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byte bit6 = (curByte != 0) ? (byte)1 : (byte)0;
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out.put(curByte);
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out.position(out.position() + bit6 - 1);
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inPtr += 1;
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curByte = inBuf.get(inPtr);
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byte bit7 = (curByte != 0) ? (byte)1 : (byte)0;
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out.put(curByte);
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out.position(out.position() + bit7 - 1);
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inPtr += 1;
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byte tag = (byte)((bit0 << 0) | (bit1 << 1) | (bit2 << 2) | (bit3 << 3) |
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(bit4 << 4) | (bit5 << 5) | (bit6 << 6) | (bit7 << 7));
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out.put(tagPos, tag);
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if (tag == 0) {
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//# An all-zero word is followed by a count of
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//# consecutive zero words (not including the first
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//# one).
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int runStart = inPtr;
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int limit = inEnd;
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if (limit - inPtr > 255 * 8) {
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limit = inPtr + 255 * 8;
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}
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while(inPtr < limit && inBuf.getLong(inPtr) == 0){
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inPtr += 8;
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}
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out.put((byte)((inPtr - runStart)/8));
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} else if (tag == (byte)0xff) {
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//# An all-nonzero word is followed by a count of
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//# consecutive uncompressed words, followed by the
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//# uncompressed words themselves.
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//# Count the number of consecutive words in the input
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//# which have no more than a single zero-byte. We look
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//# for at least two zeros because that's the point
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//# where our compression scheme becomes a net win.
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int runStart = inPtr;
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int limit = inEnd;
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if (limit - inPtr > 255 * 8) {
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limit = inPtr + 255 * 8;
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}
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while (inPtr < limit) {
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byte c = 0;
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for (int ii = 0; ii < 8; ++ii) {
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c += (inBuf.get(inPtr) == 0 ? 1 : 0);
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inPtr += 1;
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}
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if (c >= 2) {
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//# Un-read the word with multiple zeros, since
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//# we'll want to compress that one.
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inPtr -= 8;
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break;
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}
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}
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int count = inPtr - runStart;
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out.put((byte)(count / 8));
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if (count <= out.remaining()) {
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//# There's enough space to memcpy.
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inBuf.position(runStart);
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ByteBuffer slice = inBuf.slice();
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slice.limit(count);
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out.put(slice);
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} else {
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//# Input overruns the output buffer. We'll give it
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//# to the output stream in one chunk and let it
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//# decide what to do.
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if (out == slowBuffer) {
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int oldLimit = out.limit();
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out.limit(out.position());
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out.rewind();
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this.inner.write(out);
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out.limit(oldLimit);
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}
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inBuf.position(runStart);
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ByteBuffer slice = inBuf.slice();
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slice.limit(count);
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while(slice.hasRemaining()) {
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this.inner.write(slice);
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}
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out = this.inner.getWriteBuffer();
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}
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}
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}
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if (out == slowBuffer) {
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out.limit(out.position());
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out.rewind();
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this.inner.write(out);
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}
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inBuf.position(inPtr);
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return length;
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}
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public void close() throws IOException {
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this.inner.close();
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}
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public boolean isOpen() {
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return this.inner.isOpen();
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}
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}
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